find the power of the point (1,2) with respect to X²+y²+6x+8y-96=O is
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X²+y²+6x+8y-96=O
or, (x²-6x+9)+(y²+8y+16) = 96+9+16 =121
or, (x-3)²+(y+4)²=11²
centre of the circle is (3,-4)
radius=11
distance between (1,2) and (3,-4) is √40 <11
so (1,2) is in the circle
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