Question

find the power of the point of (2,-1) with respect to 3x^2+3y^2+4x+2y+6​

Answer 1

Answer:

firstly divide the whole equation with 3 in order to turn the equation in a pure circle equation form.

3/(3x"2+3y"2+4x+2y+6)

x"2+y"2+4/3x+2/3y+2

wkt, (x=2) and (y=-1)

(2)"2+(-1)"2+{4/3(2)}+{3/2(-1)}+2

4+1+{2/3}+{-3/2}+2

4+1+{2/3}-{3/2}+2

4+1-{1/1}+2

7

Step-by-step explanation:

Answer 2

Answer:

btao

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name?

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