Question

find the preimeter of rectangle whose breadth is 7 cm and leanth of one diagonal is 25 cm​

Answer 1

Answer:

62 cm

Step-by-step explanation:

Length of rectangle = root((25^2) - (7^2))

= 24cm

Perimeter = 2(l+b)

= 2*(24+7)

= 2* 31

62 cm

Hope it helps :)

Answer 2

by pythagoras theorem

h²=p²+b²

25²=p²+7²

625=p²+49

p²=625-49

p²=576

p=√576

p=24

now perimeter =

2(l+b)

2(24+7)

2(31)

62 is the answer

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