Find the present age of a woman, 15 years ago whose age was equal to the sum of the ages that her two children will be
15 years
form now. The younger child 5 years from now will be 17 and the elder 12 years ago was double the age of the younger 3
year ago
Answers
Answer:
87
Step-by-step explanation:
w-15 = (C¹ +15 ) (C² +15)
w = c1 + C2 +45
C2 +5= 17
c2 = 12
C1- 12= 2(c2-3)
c1 = 18+12
c1 = 30
w= 30+12+45
w= 87
Given:
15 years ago women's age was equal to the sum of the ages that her two children will be 15 years from now.
The younger child 5 years from now will be 17
The elder 12 years ago was double the age of the younger 3 years ago.
To find:
The present age of a woman
Solution:
Let the present age of women be w
Let the present age of the elder child be e
Let the present age of younger child be y
Equation 1 : w - 15 = (e + 15 ) + (y + 15)
w - 15 = e + y +30
w = e + y + 45
Equation 2: y + 5= 17
y = 17 - 5
y = 12
Equation 3: e - 12= 2(y - 3)
e - 12 = 2y - 6
e - 2y = 6
Solving Equation 1, 2 and 3
e - 2(12) = 6 (Substituting value of y in Equation 3)
e - 24 = 6
e = 30
w = 30 + 12 + 45 (Substituting the value of e and y in Equation 1)
w = 87
Hence, the present age of women is 87 years.