find the pressure 200 below the surface of the ocean if pressure on the free surface of liquid is one atmosphere (Density of sea water =1060kg/m3)
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What is the pressure 200 m below the surface of the ocean if the sp. gravity of sea water is 1.03 : [Atmospheric pressure=1.013×105N/m2].
A .
21.2×105N/m2
B .
20.4×105N/m2
C .
40×104N/m2
D .
21.2×106N/m2
ANSWER
The gauge pressure at any depth is given by,
Pg=ρgh
Given, the atmospheric pressure to be Po=1.013×105Pa
The pressure at this depth will be,
P=Po+Pg
= 1.013×105+1.03×103×10×200
= 21.2×10^5 Pa
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