Question

Find the pressure 200 m below surface of the ocean if pressure on the free surface of liquid is one atmosphere (Density of seawater is = 1060 kg/m3)

Answer 1

ANSWER:

21.789x 10^5 N/m²

Explanation:

h:- 200m

p:- 1060kg/m³

g:- 9.8m/s²

Patm:- 1.013x10 N/m2

FORMULA:

P=Po+hpg

= 1.013x10 + 200 x 1060x 9.8

= 21.789x 10^5 N/m²

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Answer 2

Ans is 21.789 * 10^5 N/m2
h=200m
p= 1060 kg/m3
g=9.8m/s2
Patm = 1.013 * 10 N/m3
P =Po +hpg
= 1.013*10 +200* 1060*9.8
= 21.789 *10^5 N/m2