Question

Find the pressure 200 m below the
surface of the ocean if pressure on the
free surface of liquid is one atmosphere.
(Density of sea water = 1060 kg/m?)​

Answer 1

Explanation:

h−200m 

p−1060kg/m3 

g−9.8m/s2

Patm:−1.013×10 N/m2 

FORMULA: 

P=P0+hpg 

= 1.013×10+200×1060×9.8 

= 21.789×105N/m2