Question

find the pressure excited by a 450 N woman putting all her weight on to heel of area 2 cm×2cm​

Answer 1

Explanation:

As per the provided information in the given question, we have :

• Force applied by woman (F) = 450 N
• Area of the heel (A) = 2 cm × 2 cm

Before commencing the steps, we need to convert the units of area into m².

→ Area of the heel = 2 cm × 2 cm

→ Area of the heel = 4 cm²

Now, converting cm² into m².

→ 1 m² = 10000 cm²

→ 1 cm² = 1 ÷ 10000 m²

→ 1 cm² = 0.0001 m²

So,

→ 4 cm² = 0.0004 m²

Now, finding the pressure exerted by the woman.

Pressure is defined as force per unit area. It SI unit is Pa or Pascal and 1 Pa equivalent to 1 N/m².

Mathematically,

→ P = F ÷ A

• P denotes pressure
• F denotes force
• A denotes area

Substituting the values, we have :

→ P = (450 ÷ 0.0004) Pa

After removing the decimals,

→ P = (4500000 ÷ 4) Pa

Dividing both the numerator and the denominator with 2.

→ P = (2250000 ÷ 2) Pa

→ P = 1125000 Pa

Here, we can also write Pascal as kilo-pascal since the numerical value is large.

→ 1000 Pa = 1 kPa

→ 1125000 Pa = 1125 kPa

Therefore, the pressure exerted is 1125000 Pa.

Answer 2

Answer:

11250 pa

Explanation:

Data:
pressure: ?
force: 450 N
area: 2 cm x 2 cm=4 cm^2= 0.04 m^2

Solution:

P=F/A
P=450/0.04
p=11250 pa

Result:
the pressure exerted by the women on the area of 2m x 2m is 11250 pa.