Question

find the pressure exerted at the tip of a drawing pin if it is pushed against a board with a force of 20N.assume the area of the tip to be 0.1mm 2

Answer 1

Pressure = Force / area of cross section
               = 20 N / 0.1 mm²
               = 20 N / 1 * 10⁻⁷ m²
               = 2 * 10⁸ Pa

Answer 2

Explanation:

Given, Force = 20 N

Area = 0.1 $\bold{mm^2}$

We know that,

$\begin{aligned} \text { Pressure } &=\bold{\frac{\text { Force }}{\text { Area }}}\\ &=\frac{20}{0.1 \times 10^{-6}} \\ &=20 \times 10^{7} \frac{N}{m^{2}} \end{aligned}$

The pressure exerted by the pin is $\bold{2 \times 10^{8} \frac{N}{m^{2}}}$

The pressure is calculated by using the formula $\bold{\frac{F}{A}}$ , here F denotes the force and A denotes the Area. The given force value is 20 N and the given area value is 0.1 $\bold{mm^2}$. Then, force is divided by the area to calculate pressure. So, the calculated pressure is $\bold{2 \times 10^{8} \frac{N}{m^{2}}}$