Question

Find the pressure exerted at the tip of drawing pin if it is pushed against a board with a force of 20 n. Assume the area of the tip to be 0.1mm sqare

Answer 1

$\red{HEY\:BUDDY!!}$

HERE'S THE ANSWER...

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↪️ We know , Force per unit area is know as pressure , i.e

⚫ Pressure = Force / area

⏺️Force ( F ) = 20 Newton ( N )

⏺️Area ( A ) = 0.1 ( mm )^2

=> 0.1 × 10^(-3 × 2 )

=> 0.1 × 10^( -6 )

=> 1 × 10^( - 7 ) m^2

⏩ Pressure = F / A

=> Pressure = 20 / 10^( - 7 )

=> Pressure = 20 × 10^7

=> $\boxed{Pressure\:=\:2\:×\:10^8 \: Pa}$

▶️ Pressure exerted by tip of pin is 2 × 10^8 Pascal ( Pa )

HOPE HELPED..

$\red{JAI\:HIND..}$

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Answer 2

$\huge \bold {\mathfrak {hey}}$

$\huge \bold {Answer :-}$

✔️ You should know that what is pressure ?
➡️ Force per unit area is called pressure.

✔️ Formula of pressure ?
➡️ Pressure = Force / Area

$\huge \bold {GIVEN :}$

Force = 20 N
Area = 0.1 mm^2
=0.1 × 10 ^ - 6
= 1 × 10 ^ - 7m ^2

Now,

Pressure = FORCE / AREA

➡️ Pressure = 20/10 ^ - 7

✔️ 20 × 10 ^7

➡️ $\underline \bold {Pressure => 2 × 10 power 8}$ ✔️✔️✔️

✔️✔️ Pressure exerted by tip of sqare is 2 × 10^8

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