find the price of the A&B car.
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11000. I don't whether it is right or no....
aadilturak13pbjsy0:
Your answer is wrong
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A Sells a car priced rs. 36,000
1st discount = 8% on amount of rs. 20,000
So, 20,000×8/100
= rs.1600
Therefore, 1st discount = rs. 1600
2nd discount = 5% on amount of rs. 16000
So, 16000×5/100
=rs.800
Therefore, 2nd discount = rs.800
Total discount = 1600+800
= 2400
B also sells a car worth 36,000
Discount = 7%
So, 36,000×7/100
= rs. 2520
Therefore, total discount = rs.2520
Therefore, A gives a discount of rs.2400 and B gives a discount of rs.2520.
Actual price at which car was sold by A = 36,000 - 2400 = 33600.
Actual price at which car was sold by B = 36,000 - 2,520 = 33,480.
Hope it helps.
1st discount = 8% on amount of rs. 20,000
So, 20,000×8/100
= rs.1600
Therefore, 1st discount = rs. 1600
2nd discount = 5% on amount of rs. 16000
So, 16000×5/100
=rs.800
Therefore, 2nd discount = rs.800
Total discount = 1600+800
= 2400
B also sells a car worth 36,000
Discount = 7%
So, 36,000×7/100
= rs. 2520
Therefore, total discount = rs.2520
Therefore, A gives a discount of rs.2400 and B gives a discount of rs.2520.
Actual price at which car was sold by A = 36,000 - 2400 = 33600.
Actual price at which car was sold by B = 36,000 - 2,520 = 33,480.
Hope it helps.
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