Question

find the prime factorisation of each of the following 1221​

Answer 1

Answer:

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1221 is a composite number. Prime factorization: 1221 = 3 × 11 × 37.

The exponents in the prime factorization are 1, 1, and 1.

Adding one to each and multiplying we get (1 + 1)(1 + 1)(1 + 1)

= 2 × 2 × 2 = 8.

Step-by-step explanation:

1221 is a composite number.

Prime factorization: 1221 = 3 × 11 × 37

The exponents in the prime factorization are 1, 1, and 1. Adding one to each and multiplying we get (1 + 1)(1 + 1)(1 + 1) = 2 × 2 × 2 = 8. Therefore 1221 has exactly 8 factors.

Factors of 1221: 1, 3, 11, 33, 37, 111, 407, 1221

Factor pairs: 1221 = 1 × 1221, 3 × 407, 11 × 111, or 33 × 37

1221 has no square factors that allow its square root to be simplified. √1221 ≈ 34.94281

1 × 11 × 111 = 1221

1221 is the sum of five consecutive prime numbers:

233 + 239 + 241 + 251 + 257 = 1221

1221 is the hypotenuse of a Pythagorean triple:

396-1155-1221 which is 33 times (12-35-37)

Not only is 1221 a palindrome in base 10 but look at it in these other bases:

It’s 14341 in BASE 5,

5353 in BASE 6,

272 in BASE 23, and

it’s XX in BASE 36 because 33(36) + 33(1) = 33(37) = 1221

PLEASE MY ANSWER AS A BRAINLIEST ANSWER

Answer 2

Step-by-step explanation:

The answer of prime factorization