Find the prime factorisation of each of the following numbers:
(a) 36
(b) 58
(C) 86
(d) 162
(f) 720
(8) 1028
(h) 2058 (i) 1225
(e) 342
(1) 9652
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Thus, the Prime Factors of 1028 are: 2, 2, 257. How many Prime Factors of 1028? When we count the number of prime numbers above, we find that 1028 has a total of 3 Prime Factors.
Thus, the Prime Factors of 2058 are: 2, 3, 7, 7, 7.
The prime factorization of 1225 = 52•72.
342 is a composite number. The exponents in the prime factorization are 1, 2, and 1. Adding one to each and multiplying we get (1 + 1)(2 + 1)(1 + 1) = 2 x 3 x 2 = 12. Therefore 342 has exactly 12 factors
Prime factors of 9652 :
2x2, 19, 127
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