Math, asked by pinkcity1977, 1 month ago

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Find the prime factorisation of the following numbers :
(i) 36
(ii) 39
(iii) 42
(iv) 45
(u) 52
(vii) 390
(viii) 1540 (ix) 385 (x) 1260 (xi) 1024
(vi) 64
(xii) 2520​

Answers

Answered by Sirat4
5

Answer:

36 = 2 x 2 x 3 x 3

39 = 3 x 13

42 = 2 x 3 x 7

45 = 3 x 3 x 5

52 = 2 x 2 x 13

390 = 2 x 3 x 5 x 13

1540 = 2 x 2 x5 x 7 x 11

385 = 5 x 7 x 11

1260 = 2 x 2 x 3 x 3 x 5

1024 = 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2

64 = 2 x 2 x 2 x 2 x 2 x 2

2520 = 2 x 2 x 2 x 3 x 5 x 7

Have a nice day !!!   *_*

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