Question

find the prime factors by repeated division: a. 70 b. 128

Answer 1

$\textbf{Given numbers 70 and 128}$

$\textbf{To find:}$

$\text{Prime factors of 70 and 128}$

$\begin{array}{r|l}2&70\\\cline{2-2}5&35\\\cline{2-2}7&7\\\cline{2-2}&1\\\cline{2-2}\end{array}$

$\begin{array}{r|l}2&128\\\cline{2-2}2&64\\\cline{2-2}2&32\\\cline{2-2}2&16\\\cline{2-2}2&8\\\cline{2-2}2&4\\\cline{2-2}2&2\\\cline{2-2}&1\\\cline{2-2}\end{array}$

$\text{Now,}$

$70=2{\times}5{\times}7$

$128=2{\times}2{\times}2{\times}2{\times}2{\times}2{\times}2=2^7$

$\implies\textbf{70 has prime factors 2, 5 and 7 and}$

$\textbf{128 has 2 as only factor}$

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Answer 2

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