Question

find the prime factors of the following. - 330. 2100. 286. 2310. 288. 8064.​

Answer 1

Step-by-step explanation:

Pair factors of 2310 are the pairs of numbers that when multiplied give the product 2310. The factors of 2310 in pairs are:

1 × 2310 = (1, 2310)

2 × 1155 = (2, 1155)

3 × 770 = (3, 770)

5 × 462 = (5, 462)

6 × 385 = (6, 385)

7 × 330 = (7, 330)

10 × 231 = (10, 231)

11 × 210 = (11, 210)

14 × 165 = (14, 165)

15 × 154 = (15, 154)

21 × 110 = (21, 110)

22 × 105 = (22, 105)

30 × 77 = (30, 77)

33 × 70 = (33, 70)

35 × 66 = (35, 66)

42 × 55 = (42, 55)

Negative pair factors of 2310 are:

-1 × -2310 = (-1, -2310)

-2 × -1155 = (-2, -1155)

-3 × -770 = (-3, -770)

-5 × -462 = (-5, -462)

-6 × -385 = (-6, -385)

-7 × -330 = (-7, -330)

-10 × -231 = (-10, -231)

-11 × -210 = (-11, -210)

-14 × -165 = (-14, -165)

-15 × -154 = (-15, -154)

-21 × -110 = (-21, -110)

-22 × -105 = (-22, -105)

-30 × -77 = (-30, -77)

-33 × -70 = (-33, -70)

-35 × -66 = (-35, -66)

-42 × -55 = (-42, -55)

Answer 2

Answer:

330 - 2,3,5,11 and 2100 - 2,2,3,5,5 , 286 - 2,143 , 2310 - 2,5,3,77