find the prime number that will divide 433 leaving the remainder 4 in each case
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Answered by
3
Answer:
13 is the prime number that will divide 433 leaving the remainder 4.
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Answered by
0
Answer:
Step-by-step explanation:Prime factors of 4,7 and 13
4=2×2
7 and 13 are prime numbers
LCM (4,7,13)=364
we know that, the largest 4 digit number is 9999.
Step 1 : divide 9999 by 364, we get
364
9999
=171
Step 2: subtract 171 from 9999
9999−171=9828
Since a remainder of 3 is to be left
9282+3=9831
therefore 9831 is the number.
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