Question

Find the prime of factorizarion of the 256​

Answer 1

Here are the first several prime factors: 2, 3, 5, 7, 11, 13, 17, 19, 23, 29...

Let's start by dividing 256 by 2

256 ÷ 2=128 - No remainder!2 is one of thefactors

128 ÷ 2 =64 - No remainder!2 is one of the factors!

64 ÷ 2 = 32 - No remainder!2 is one of the factors!

32 ÷ 2 = 16 - No remainder! 2 is one of the factors!

16 ÷ 2 = 8 - No remainder! 2 is one of the factors!

8 ÷ 2 = 4 - No remainder! 2 is one of the factors!

4 ÷ 2 = 2 - No remainder! 2 is one of the factors!

2 ÷ 2 = 1 - No remainder! 2 is one of the factors!

The orange divisor(s) above are the prime factors of the number 256. If we put all of it together we have the factors 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 = 256. It can also be written in exponential form as 28......

Hope IT helps please Mark BRAINLEIST

Answer 2

Answer:

Prime factorisation of 256

In simple method.