Find the primeter of the rectangle whose length is 40cm
land
cliagonal is 41 cm
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Step-by-step explanation:
As we can see in the rectangle,
By Pythagoras theorem,
Now as given in the question,
Diagonal = 41 cm.
Length = 40 cm.
So, Putting these value we get,
(width)2 = (40)2 + (41)2
(width)2 = 1681 + 1600
(width) = 81
(width) = 9 cm
Hence the width of the rectangle is 9 cm.
So
The perimeter of the rectangle = 2 ( Length + Width )
= 2 ( 40 cm + 9 cm )
= 2 x 49 cm
= 98 cm
Hence the perimeter of the rectangle is 98 cm.
hope it will help you....
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