Question

Find the principal amount (p) for the following cases. (a) r =2 1/4 %, n =3 years, I = 50 .solution​

Answer 1

Step-by-step explanation:

That is the answer for that

Answer 2

Answer:

Given :-

• The rate of interest is 2 1/4 %, time period is 3 years and the simple interest is Rs 50.

To Find :-

• What is the principal amount.

Formula Used :-

$\clubsuit$ Principal Formula :

$\bigstar \: \: \sf\boxed{\bold{\pink{P =\: \dfrac{S.I \times 100}{R \times n}}}}\: \: \: \bigstar$

where,

• P = Principal
• S.I = Simple Interest
• R = Rate of Interest
• n = Time Period

Solution :-

Given :

• Rate of Interest = 2 ¼ %
• Time Period = 3 years
• Simple Interest = Rs 50

According to the question by using the formula we get,

$\implies \bf P =\: \dfrac{S.I \times 100}{R \times n}$

$\implies \sf P =\: \dfrac{50 \times 100}{2\dfrac{1}{4} \times 3}$

$\implies \sf P =\: \dfrac{5000}{\bigg(2 + \dfrac{1}{4}\bigg) \times 3}$

$\implies \sf P =\: \dfrac{5000}{\bigg(\dfrac{2 \times 4 + 1}{4}\bigg) \times 3}$

$\implies \sf P =\: \dfrac{5000}{\bigg(\dfrac{8 + 1}{4}\bigg) \times 3}$

$\implies \sf P =\: \dfrac{5000}{\dfrac{9}{4} \times 3}$

$\implies \sf P =\: \dfrac{5000}{\dfrac{9 \times 3}{4}}$

$\implies \sf P =\: \dfrac{5000}{\dfrac{27}{4}}$

$\implies \sf P =\: \dfrac{5000}{1} \times \dfrac{4}{27}$

$\implies \sf P =\: \dfrac{20000}{27}$

$\implies \sf\bold{\red{P =\: Rs\: 740.74}}$

$\therefore$ The principal amount is Rs 740.74 .