Question

find the principal and simple interest for rate of interest 3.5 % p.a. and time 2 yrs and amount ₹535
plz tell answer fast​

Answer 1

Step-by-step explanation:

SI = prt/100

SI = (535×2×3.5)/100

SI = 37.45 rupees

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Answer 2

Answer :-

• The principal = Rs 500.
• The simple interest = Rs 535.

To find :-

• The principal and simple interest.

Step-by-step explanation :-

• Let's find the principal and simple interest!

We know that :-

$\underline{\boxed{ \sf SI = Amount - Principal}}$

Where,

• SI = Simple Interest.

Here,

• Amount = Rs 535.

Let :-

• The principal be Rs "p".

Therefore,

$\longrightarrow \bf SI = Rs \: 535 - p$

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• Now, let's find the simple interest!

We know that :-

$\underline{\boxed{\sf SI = \dfrac{Principal \times Rate \times Time}{100}}}$

Where,

• SI = Simple Interest.

Here,

• Simple interest = Rs 535 - p.
• Rate = 3.5% p.a.
• Time = 2 yrs.

Substituting the given values in this formula,

$: \longmapsto \tt 535 - p = \dfrac{p \times 3.5 \times 2}{100}$

$\tt : \longmapsto 535 - p = \dfrac{p \times 7}{100}$

$\tt : \longmapsto 535 - p = \dfrac{7p}{100}$

$\tt : \longmapsto 535 = \dfrac{7p}{100} + p$

$\tt : \longmapsto 535 = \dfrac{7p \times 1 + p \times 100}{100}$

$\tt : \longmapsto 535 = \dfrac{7p + 100p}{100}$

$\tt : \longmapsto 535 = \dfrac{107p}{100}$

$\tt : \longmapsto 535 \times 100 = 107p$

$\tt : \longmapsto 53500 = 107p$

$\tt : \longmapsto \dfrac{53500}{107} = p$

$\tt : \longmapsto Rs \: 500 = p$

Hence :-

$\rm Principal = p = Rs \: 500.$

$\rm SI = 535 - p = 535 - 500 = Rs \: 35.$

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