Question

Find the principal
anual rate of intrest =11%
period= 3 years
total interest= 825 rupees
find the principal rupeer​

Answer 1

(SI×100)÷T×R

SI=825

RATE=11%

Time=3 years

Step-by-step explanation:

(825×100)÷11×3

82500÷11×3

7500×3

22500

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Answer 2

➤ Given :-

Rate of interest :- 11%

Time :- 3 years

Simple Interest :- ₹ 825

➤ To Find :-

Principle amount of the given sum..........

➤ Formula required :-

$\large \tt \dashrightarrow \orange{ \boxed{ \gray{ \tt \frac{SI \times 100}{R \times T} }}}$

➤ Solution :-

Rate of interest :-

$\tt \longrightarrow \dfrac{825 \times 100}{11 \times 3}$

$\tt \longrightarrow \dfrac{ \cancel{825} \times 100}{11 \times \cancel{3}} = \dfrac{275 \times 100}{11 \times 1}$

$\tt \longrightarrow \dfrac{ \cancel{275} \times 100}{ \cancel{11} \times 1} = \dfrac{25 \times 100}{1 \times 1} = \boxed{ \tt 25 \times 100}$

$\tt \longrightarrow \sf rs \tt \: \: 2500$

$\Huge\therefore$The principle of the given sum is ₹ 2500.

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$\dashrightarrow$Some related formulas :-

Simple Interest :- $\boxed{\tt\dfrac{P \times R \times T}{100}}$

Rate of interest :- $\boxed{\tt\dfrac{SI \times 100}{P \times T}}$

Time :- $\boxed{\tt\dfrac{SI \times 100}{P \times R}}$

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More to know..............

• Simple interest is used in all over the world. It is mainly used to calculate the extra amount to be given from borrower to lender, when a person borrows money from a bank or any other person.
• Principal amount is given at first from lender to borrower in which the borrower gives it back with interest.
• Rate of interest is the extra amount to be paid for lender at end of time period,which is always written in percentage form.
• Time is given for borrower to return back the amount to lender with the given interest.