Find the principal if compound interest is ₹331, rate is 10% per annum compounded annually and time is 3 years.
Answers
Answered by
20
Solution: We are given that CI = ₹331, R = 10% per annum, and n = 3 years.
Let the principal be P.
Then, the amount , A = P +CI = ₹ (P + 331)
and A = P (1+R/100)ⁿ
=> P + 331 = P (1+10/100)³
=> P = 331 × (1000/331) = 1000
Hence, the principal is ₹1000.
Extra Information
Interest compounded yearly (or annually)
= R% per annum
= n years
=> A = P(1+R/2/100)^2×n
Interest compounded half - yearly (or semi - annually)
= R/2% per half - year
= (2×n) half - years
=> A = P(1+R/2/100)^2×n
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6
Answer:
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