Find the principal if the compound interest at the rate of 10% per annum for 2 years is Rs.1250.
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Answers
Answer:
Amount = P× ( 1 + R/100) ^T
1250 = P × ( 1 + 10 / 100 ) ^ 2
1250 = P × ( 100 + 10 / 100 ) ^ 2
1250 = P × ( 110 /100 ) ^2
1250 =. P × ( 11 /10) ^ 2
1250 × 10 / 11 × 10 / 11 = P
125000 = P
Answer :
›»› The required principal is Rs. 125000.
Step-by-step explanation :
Given :
- Amount = Rs. 1250.
- Rate interest = 10% per annum.
- Time = 2 years.
To Find :
- Principal = ?
Formula required :
To find the principal we use the formula of amount.
Formula of amount to calculate the principal is given by,
→ A = P(1 + R/100)ⁿ.
Here,
- A is the Amount.
- P is the Principal.
- R is the Rate interest.
- n is the Time.
Solution :
As we are given with the amount, rate interest, and time and we need to find the principal then we know the required formula, that is,
→ A = P(1 + R/100)ⁿ.
By using the formula of amount to calculate the principal and substituting all the given values in the formula, we get :
→ 1250 = P(1 + 10/100)²
→ 1250 = P(100 + 10/100)²
→ 1250 = P(110/100)²
→ 1250 = P(11/10)²
→ 1250 = P * 11²/10²
→ 1250 = P * 121/10²
→ 1250 = P * 121/100
→ 1250 * 100 = P * 121
→ 125000 = P * 121
→ 125000 = 121P
→ P = 125000/121
→ P = 1033.05.