Question

find the principal if the difference between CI and Si on it at 15 % per annum for three years is 1134 rupees​

Answer 1

If the difference between C.I and S.I on a certain principal amount at 15% p.a for 3 years is Rs. 1134 then the value of principal is Rs. 16000.

Step-by-step explanation:

It is given that,

The difference between C.I and S.I = Rs. 1134

Rate of interest, R = 15%

Time period = 3 years

Let the principal be denoted as “P”.

Required formula:

(i) S.I. = $\frac{PRT}{100}$

(ii) C.I. = P[(1+$\frac{R}{100}$)ⁿ - 1]

By subtracting the above two formulas and substituting the given values we get,

C.I. – S.I. = [P{(1+$\frac{R}{100}$)ⁿ – 1}] – [$\frac{PRT}{100}$]

⇒ 1134 = [P{(1+$\frac{15}{100}$)³ – 1}] – [$\frac{P*15*3}{100}$

⇒ 1134 = P [{1.5}³ – 1} – 0.45]

⇒ 1134 = P [0.520875 – 0.45]

⇒ 1134 = P * 0.070875

⇒ P = Rs. 16000

Thus, the value of the principal is Rs. 16000 .

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Answer 2

Answer:

16000

Step-by-step explanation:

then the value of principal is Rs. 16000.

Step-by-step explanation:

It is given that,

The difference between C.I and S.I = Rs. 1134

Rate of interest, R = 15%

Time period = 3 years

Let the principal be denoted as “P”.

Required formula:

(i) S.I. = \frac{PRT}{100}

100

PRT

(ii) C.I. = P[(1+\frac{R}{100}

100

R

)ⁿ - 1]

By subtracting the above two formulas and substituting the given values we get,

C.I. – S.I. = [P{(1+\frac{R}{100}

100

R

)ⁿ – 1}] – [\frac{PRT}{100}

100

PRT

]

⇒ 1134 = [P{(1+\frac{15}{100}

100

15

)³ – 1}] – [\frac{P*15*3}{100}

100

P∗15∗3

⇒ 1134 = P [{1.5}³ – 1} – 0.45]

⇒ 1134 = P [0.520875 – 0.45]

⇒ 1134 = P * 0.070875

⇒ P = Rs. 16000

Thus, the value of the principal is Rs. 16000 .

----------------------------------------------------------------------------------

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The difference between compound interest and simple interest on a certain sum of money for 3 years at 5% per annum its rupees 61 find the sum

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