Question

Find the principal if the interest compounded annually at the rate of 10% for two years is Rs 210.
PLEASE ANSWER MY QUESTION FASTLY​

Answer 1

Answer:

p=₹17.35

Step-by-step explanation:

$A=P(1-\frac{r}{100} )^n$

But  principle is unknow   but $r=10$%, A=₹210 and n=2 is given.

$A=P(1-\frac{10}{100} )^n$

$A=P(1-\frac{1}{10} )^n$

$A=P(\frac{11}{10} )^2$

$210=p(\frac{121}{100})$

$\frac{2100}{121} =p$

p=₹17.35

Please mark me the brainliest.