Question

find the principal in the following


SI=448
Time=8months
Rate=8%

Answer 1

Hey mate here is ur answer.

SI = P×R×T/100

$448 = x \times8 \times 8 \div 100×12 \\ 448×1200= 64x \\ x = 537600 \div 64 \\ x = 8400$
Hope it's help u.

Answer 2

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\therefore{\text{Principal=8,400\:rupees}}}$

$\orange{\bold{\underline{\underline{Step-b-step\:explanation:}}}}$

$\green{ \underline \bold{Given : }} \\ : \implies \text{Time (t)= 8 \: months} \\ \\ : \implies \text{Simple \: interest(S.I) = 448\:rupees} \\ \\ : \implies \text{Rate(r) = 8\%} \\ \\ \red{ \underline \bold{To \: Find: }} \\ : \implies \text{Principal(p) = ?}$

• According to given question :

$\bold{As \: we \: know \: that } \\ \circ \: \text{Simple \: interest} = \frac{ \text{Principal }\times \text{ Rate} \times \text{Time}}{100} \\ \\ \bold{Putting \: given \: values} \\ : \implies S.I = \frac{p \times r \times t}{100} \\ \\ : \implies 448 = \frac{p \times 8\times\frac{8}{12}}{100} \\ \\ : \implies p = \frac{448 \times 100\times12}{8 \times 8 } \\ \\ \green{ : \implies \text{p = 8400\: rupees}} \\ \\ \green{ \therefore \text{principal = 8,400\: rupees}} \\ \\ \bold{Basic \: formula\:related\:to\:C.I} \\ \circ \: A = p(1 + \frac{r}{100} )^{t}$