Math, asked by qwert9371, 10 months ago

Find the principal of time =3years , si= 600 rupees ,rate = 4℅

Answers

Answered by rb470
1

Step-by-step explanation:

so the principal is RS 5000

Attachments:
Answered by BrainlyConqueror0901
2

\blue{\bold{\underline{\underline{Answer:}}}}

\green{\therefore{\text{Principal=5,000\:rupees}}}\\

\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}

 \green{ \underline \bold{Given : }} \\   : \implies  \text{Time (t)= 3 \: years} \\   \\   : \implies  \text{Simple \: interest(S.I) = 600} \\   \\   : \implies  \text{Rate(r) = 4\%} \\  \\ \red{ \underline \bold{To \: Find: }} \\  :  \implies  \text{Principal(p) = ?}

• According to given question :

 \bold{As \: we \: know \: that  } \\   \circ \:  \text{Simple \: interest} =  \frac{ \text{Principal }\times \text{ Rate} \times  \text{Time}}{100}  \\  \\  \bold{Putting \: given \: values} \\   : \implies S.I =  \frac{p \times r \times t}{100}  \\  \\   : \implies 600 =  \frac{p \times 4 \times3 }{100}  \\  \\  :  \implies p =  \frac{600 \times 100}{3 \times4 }  \\  \\  \green{ :  \implies  \text{p = 5000 \: rupees}} \\  \\  \green{ \therefore  \text{principal = 5000 \: rupees}} \\  \\   \bold{Basic \: formula\:related\:to\:C.I} \\  \circ \:  a = p(1 +   \frac{r}{100} )^{t}

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