Question

Find the principal on which interest in 5 years at 11% per year is ₹8800

Answer 1

$si = \frac{p \times r \times t}{100} \\ \\ 8800 = \frac{p \times 5 \times 11}{100} \\ \\ p = \frac{8800 \times 100}{5 \times 11} \\ \\ p = \frac{880000}{5 \times 11} \\ \\ p = rs \: 16000(ans)$

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