Math, asked by preethaprasad, 9 months ago

find the PRINCIPAL SOLUTION of cos 3theta=sin 2theta​

Answers

Answered by Anonymous
0

Answer:

Hi There!!!

Step-by-step explanation:

Now we have

cos 3A=sin 2A ( now write cos 3A as sin (pi/2-3A)

sin (90-3A) = sin (2A)

now using the general solution formula

5A=npi+(-1)^n pi/2

On simplification A = pi/10(2n + (-1) ^ n )

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