find the principal solution of sec x =2
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Answer:
secx=2
We know, sec
3
π
=2 and sec
3
5π
=sec(2π−
3
π
)=sec
3
π
=2.
Therefore, the principal solutions are x=
3
π
and
3
5π
.
Now, secx=sec
3
π
cosx=cos
3
π
x=2nπ±
3
π
, where n∈Z.
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