find the principal solution of sin theta = 1/√2
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Answer:
The solutions are x = π/4 and 3π/4.
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Given sin x = 1/√2
=> x = π/4
sin (π – x) = sin x
=> sin π/4 = sin (π – π/4)
= sin 3π/4
sin π/4 = sin 3π/4 = 1/√2
The solutions are x = π/4 and 3π/4.
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