find the principal solutions of the equation sin x=√3÷2
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Answer:
Principal solutions of sin x = √3÷2 is x=π/3 and x=2π/3
Step-by-step explanation:
We know that, sin π/3=√3/2
and sin 2π/3=sin(π-π/3)=sin π/3=√3/2
Therefore, principal solutions are x= π/3 and 2π/3.
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