find the principal that will a compound interest of 1632 rs in two yrs at 4% interest per annam
Answers
Answered by
6
Compound interest C = 1632 Rs
Rate R = 4 %
Year n = 2
Principal = ?
Thus
C = P [1 + R ]^n
1632 = P [ 1+0.04 ] ^2
P = 1632/1.08
P = 1511.11 Rs
Thus the principal amount is 1511.11 Rs
Rate R = 4 %
Year n = 2
Principal = ?
Thus
C = P [1 + R ]^n
1632 = P [ 1+0.04 ] ^2
P = 1632/1.08
P = 1511.11 Rs
Thus the principal amount is 1511.11 Rs
Answered by
9
Solution :-
Compound Interest = Amount - Principal
C. I. = P(1 + R/100)ⁿ - P
Given -
Rate of Interest = 4 %, Time = 2 years and Compound Interest = Rs. 1632
⇒ 1632 = P(1 + 4/100)² - P
⇒ 1632 = (P × 104/100 × 104/100) - P
⇒ 1632 = (P × 1.0816) - P
⇒ 1632 = 1.0816P - P
⇒ 0.0816P = 1632
⇒ P = 1632/0.0816
⇒ P = Rs. 20000
So, the Principal is Rs. 20000
Answer.
Compound Interest = Amount - Principal
C. I. = P(1 + R/100)ⁿ - P
Given -
Rate of Interest = 4 %, Time = 2 years and Compound Interest = Rs. 1632
⇒ 1632 = P(1 + 4/100)² - P
⇒ 1632 = (P × 104/100 × 104/100) - P
⇒ 1632 = (P × 1.0816) - P
⇒ 1632 = 1.0816P - P
⇒ 0.0816P = 1632
⇒ P = 1632/0.0816
⇒ P = Rs. 20000
So, the Principal is Rs. 20000
Answer.
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