find the principal that will amount to Rupees 2240 at 4% per annum simple interest in 3 years
Answer Let the principal be x
Time = 3 years
Rate of interest = 4%
Amount = Rs.2240
Simple interest = Amount - Principal = 2240-x
Formula :SI = PxRxT
100
100(2240-x)=12x100(2240−x)=12x
224000-100x=12x224000−100x=12x
224000=112x224000=112x
\frac{224000}{112}=x
112
224000
=x
2000 = x
Hence The principal is Rs.2000
Answers
Answer:
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Answer:
Answer:
\begin{gathered}\green{\therefore{\text{Principal=2000\:rupees}}}\\\end{gathered}
∴Principal=2000rupees
\begin{gathered}\green{\therefore{\text{S.I=240\:rupees}}}\\\end{gathered}
∴S.I=240rupees
\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}
Step−by−stepexplanation:
\begin{gathered}\green{ \underline \bold{Given : }} \\ : \implies \text{Time (t)= 3\:years} \\ \\ : \implies \text{Amount(A) = 2240\:rupees} \\ \\ : \implies \text{Rate(r) = 4\%} \\ \\ \red{ \underline \bold{To \: Find: }} \\ : \implies \text{Simple\:interest(S.I) = ?}\\\\ :\implies \text{Amount=?}\end{gathered}
Given:
:⟹Time (t)= 3years
:⟹Amount(A) = 2240rupees
:⟹Rate(r) = 4%
ToFind:
:⟹Simpleinterest(S.I) = ?
:⟹Amount=?
• According to given question :
\begin{gathered}:\implies Amount=S.I+Principal\\\\ :\implies 2240=SI+p\\\\ :\implies S.I=2240-p\\\\ \bold{As \: we \: know \: that } \\ \circ \: \text{Simple \: interest} = \frac{ \text{Principal }\times \text{ Rate} \times \text{Time}}{100} \\ \\ \bold{Putting \: given \: values} \\ : \implies S.I = \frac{p \times r \times t}{100} \\ \\ : \implies 2240-p = \frac{p \times 4\times3}{100} \\ \\ : \implies 2240-p= \frac{12p }{100 } \\ \\ :\implies 224000-100p=12p\\\\ :\implies 112p=224000\\\\ :\implies p=\frac{224000}{112} \\\\ \green{ : \implies \text{p= 2000\: rupees}} \\ \\ \green{ \therefore \text{Principal=2000\: rupees}} \\ \\ :\implies Amount=S.I+principal\\\\ \green{:\implies\text{S.I=2240-2000=240\:rupees}} \\ \\ \bold{Basic \: formula\:related\:to\:C.I} \\ \circ \: A = p(1 + \frac{r}{100} )^{t}\end{gathered}
:⟹Amount=S.I+Principal
:⟹2240=SI+p
:⟹S.I=2240−p
Asweknowthat
∘Simple interest=
100
Principal × Rate×Time
Puttinggivenvalues
:⟹S.I=
100
p×r×t
:⟹2240−p=
100
p×4×3
:⟹2240−p=
100
12p
:⟹224000−100p=12p
:⟹112p=224000
:⟹p=
112
224000
:⟹p= 2000rupees
∴Principal=2000rupees
:⟹Amount=S.I+principal
:⟹S.I=2240-2000=240rupees
BasicformularelatedtoC.I
∘A=p(1+
100
r
)
t