Math, asked by GurJas7245, 1 year ago

Find the principal value of:
sin-1(root3 - 1/ 2root2)

Answers

Answered by waqarsd
1

 {sin}^{ - 1} ( \frac{ \sqrt{3}  - 1}{2 \sqrt{2} } )  =  \frac{\pi}{10}
so \: the \: principal \: value \: in \:  \sin \:  <  < (0 \: . \: \pi) >  >  \\ here \:  \alpha  =  \frac{\pi}{10}
hope it helps
Answered by samyuktg
0

Answer:

\pi \div 12

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