find the principal when: (1) S.I.= rupees 36,rate=3%P.a. and time = 3 months
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let principal be Rs.P
I= Rs.36
r=3%
t=3/12 therefore, (1 year =12 months)
I=Prt/100
36=P×3×3/100×12
or,9P=36×100×12
or,P=36×100×12/9
or,P=Rs.4800
I= Rs.36
r=3%
t=3/12 therefore, (1 year =12 months)
I=Prt/100
36=P×3×3/100×12
or,9P=36×100×12
or,P=36×100×12/9
or,P=Rs.4800
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