Question

Find the principal when S.I = ₹648 , time = 6 years and rate = 12%

Answer 1

Answer :-

• The principal is Rs. 900

Step-by-step explanation:

To Find :-

• The principal

Solution:

Given that,

• The simple interest = Rs. 648
• Time = 6 years
• Rate = 12%

$\large{\frak{\underline{As \: we \: know \: that,}}}$

$\dag \: \boxed{\bf{Principal (P) = \dfrac{S.I. \times 100}{R \times T}}}$

Where,

• P = Principal
• S.I. = Simple Interest
• T = Time
• R = Rate

Therefore,

$\mapsto \: \bf{P = \dfrac{648 \times 100}{12 \times 6}} \\ \\ \\ \\ \mapsto \: \bf{P = \dfrac{64800}{12 \times 6}} \\ \\ \\ \\ \mapsto \: \bf{P = \dfrac{64800}{72}} \\ \\ \\ \\ \mapsto \: \bf{P = \cancel{ \dfrac{64800}{72}}} \\ \\ \\ \\ \mapsto \: \boxed{\bf{P = 900}}$

Hence, Principal = Rs. 900.

Know more :-

Some more information related to Simple interest :-

$\bull \: \: \: \: \: \: \bf{S.I. = \dfrac{P \times R \times T}{100}}$

$\bull \: \: \: \: \: \: \bf{R = \dfrac{S.I. \times 100}{P \times T}}$

$\bull \: \: \: \: \: \: \bf{T = \dfrac{S.I. \times 100}{R \times P}}$

$\bull \: \: \: \: \: \: \bf{P = \dfrac{S.I. \times 100}{R \times T}}$

Answer 2

Answer:

129600

Step-by-step explanation:

S.I*100/TIME*RATE

648*100/6*12

64800/72=129600

Principal=129600