Question

find the principal when the in simple interest is equal to 44200 rate is equal to 12% and time is equal to 3 1 by 2 years ​

Answer 1

AnswEr :

$\bold{Given} \begin{cases} \sf{Simple \: Interest=Rs. 44200} \\ \sf{Rate=12\% \: p.a.} \\ \sf{Time=3 \frac{1}{2} = \frac{7}{2}\: Yr. } \\ \sf{Principal =? }\end{cases}$

• Let's Head to the Question Now :

$\longrightarrow \sf{Simple \: Interest = \dfrac{P \times r \times t}{100} }$

$\longrightarrow \sf{44200 = \dfrac{P \times \cancel{12} \times \frac{7}{ \cancel2} }{100} }$

$\longrightarrow \sf{44200 = \dfrac{P \times 6 \times 7}{100} }$

$\longrightarrow \sf{ \dfrac{44200 \times 100}{6 \times 7}=P}$

$\longrightarrow \sf{\cancel\dfrac{4420000}{42}=P}$

$\longrightarrow \boxed{\sf{Principal = Rs. \: 105,239}}$

⠀

∴ Principal will be Rs. 105,239 (Approx).

Answer 2

Answer:

$\large\bold\red{Rs.\:1,05,238\:(Approx.)}$

Step-by-step explanation:

Given,

• Simple Intrest , S.I = ₹ 44200

• Rate of interest p.a , R = 12%

• Time, T = $3\frac{1}{2}$ yrs. = $\frac{7}{2}$ yrs.

Now,

We have to find the principal.

Let, the principal be ₹ P.

Also,

We know that,

• $\large \boxed{ \bold \purple{S.I = \frac{P\times R\times T}{100} }}$

Substituting the values,

We get,

$= > 44200 = \frac{P\times 12 \times 7}{100 \times 2} \\ \\ = > P = 44200 \times \frac{100}{12} \times \frac{2}{7} \\ \\ = > P = 105238$

Hence,

The principal is ₹ 1,05,238 (Approx)