find the principle if the compound interest (compound annually) at the rate of 10% per annum for 3 years is ₹331.
Answers
Answered by
3
hey mate..
the answer is ..
331 = p ( 1 + 10 /100) ^3
331 = p ( 11/10 x 11/10 x 11/10)
331 = 1331 /1000 p
331 × 1000/1331
= 248.6
hope it helps u
the answer is ..
331 = p ( 1 + 10 /100) ^3
331 = p ( 11/10 x 11/10 x 11/10)
331 = 1331 /1000 p
331 × 1000/1331
= 248.6
hope it helps u
happy70:
hii
Answered by
1
hi here is ur answer
331=p[(1+r/100) ^3] -1
331=p[(1+10/100) ^3] -1
331=p[(11/10) ^3] -1
331=p(1331/1000) -1
331=331/1000p
p=331*1000/331
p=1000
331=p[(1+r/100) ^3] -1
331=p[(1+10/100) ^3] -1
331=p[(11/10) ^3] -1
331=p(1331/1000) -1
331=331/1000p
p=331*1000/331
p=1000
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