Find the prob. that in a random arrangement of the
letters of the word 'UNIVERSITY' the two I's come together.
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Answered by
1
Answer:
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Step-by-step explanation:
The total number of words which can be formed by permuting the letters of the word 'UNIVERSITY' is 10! 2!
as there is two I's.
Hence n(S)=10!2!
Taking two I's as one letter, number of ways of arrangement in which both I's are together = 9!
Son(X)=9!
Hence required probability
=n(X)n(S)=9!10!/2!=15
Answered by
0
Step-by-step explanation:
The total no. of words which can be formed by permuting the letters of word 'University' is 10 !2!
as there is two l's
Hence n(S) =10!2!
Taking 2 l's as one letter number of ways of arrangement in which both l's are together=9!
Son (X) =9!
Hence required probability
n=(X) n (S(=9!10!/2!=15
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