find the probabilities of having 53 days in non leap year
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0 is the probability of having .....
srinidhi15:
i want full answer
ok
the question has a correction Instead of days there is weak
In one week there are 7 days
if we multiply 7 and 53 , we get 371
No year has 371 days
so the probability is 0
Answered by
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1 yr = 365 days
1week = 7days
in 1yr there are 52 weeks
52*7 =364
One day left it can be any day
p(e)=1/7
probability of 53 days in a year is 1/7
how 53 days
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