Question

FIND THE PROBABILITY DISTRIBUTION OF THE NO. OF TAILS IN TWO TOSSES OF A COIN.​

Answer 1

Answer ❤️

Let random variables X denotes the number of Tails, then X can take the values 0,1 & 2 .

P = probability of getting an tail in a throw of coin = ½, w = 1 - P = ½

p(0) = qq = ½×½×¼

p(1) = pq + qp = { ½×½} + { ½×½} = ¼+¼= ½

p(2) = pp = {½×½} = ¼

Thus, the probability distribution is:

X = P(X)

0 = ¼

1 = ½

2 = ¼

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