Question

find the probability distribution of the number of times a rotal of 9 appears in two throws of two dice

Answer 1

the total possibilities are 36
and the sum should be 9 that possibilities are
3,6..4,5...5,4..6,3...
so 4/36=1/9
so p(E) = 1/9

Answer 2

Answer:

$\text{The probability of getting sum 9 = }\frac{1}{9}$

Step-by-step explanation:

Two dices are thrown two times

⇒ Total number of outcomes = 6²

So, Total number of outcomes = 36

The possible outcomes where the sum of the number is 9 are :

3,6 , 4,5 , 6,3 , 5,4

Total number of possible outcomes = 4

So, Required probability = 4 ÷ 36

$\text{Hence, the probability of getting sum 9 = }\frac{1}{9}$