Question

find the probability existing 53 Sunday's in a common year​

Answer 1

Answer:

In a non-leap year there will be 52 Sundays and 1 day will be left. This 1 day can be Sunday, Monday, Tuesday, Wednesday, Thursday, friday , Saturday, Sunday. Of these total 7 outcomes, the favourable outcomes are 1. Hence the probability of getting 53 sundays = 1 / 7.

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