Find the probability for 53 Mondays in a leap year
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Answered by
1
let M be the event of getting Monday in leap year
then,noof outcomes favorable to M =53
P(M)=53/366
Answered by
2
Step-by-step explanation:
No. of favourable outcomes i.e. number of Mondays=53
total no. of possible outcomes i.e. total number of days =leap year =366days
PROBABILITY=NO.OF FAVOURABLE OUTCOMES/TOTAL NO.OF POSSIBLE OUTCOMES
53/366 ANSWER
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