Find the probability i) a leap year selected at random will have 53 fridays ii) a leap year selected at random will have only 52 fridays iii) a non leap year selected at random will have 53 fridays
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TOtal no. of outcome= 366 days as a leap year has 366 days ...
Now,, let A be the event of Having 53 fridays in leap year ..
LET P BE THE PROBABILITY..
NOW ,, THE PROBABILITY=The given outcome÷Total no. of outcomes ..
= 53÷366= 0.144
2) Let B be the event having 52 fridays ..
PRobability= The given outcome÷ The total no.of outcomes ..
= 52÷ 366= 0.142
3) Let C be the event having 53 fridays in a non leap year..
Probability= The given outcome÷ The total no. of outcomes = 53÷ 365= 0.145
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TOtal no. of outcome= 366 days as a leap year has 366 days ...
Now,, let A be the event of Having 53 fridays in leap year ..
LET P BE THE PROBABILITY..
NOW ,, THE PROBABILITY=The given outcome÷Total no. of outcomes ..
= 53÷366= 0.144
2) Let B be the event having 52 fridays ..
PRobability= The given outcome÷ The total no.of outcomes ..
= 52÷ 366= 0.142
3) Let C be the event having 53 fridays in a non leap year..
Probability= The given outcome÷ The total no. of outcomes = 53÷ 365= 0.145
// HOPE IT HELPS U
PLZ MARK IT AS BRAINLIEST //
FOLLOW ME FOR MORE ANSWERS ..
THANKS..
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