Find the probability if a card taken out at random from a pack of 52 cards is a.jack of spade. B. Ace of red colour c.number 5
Answers
Answered by
0
A)
=>Solution:
No. of jack of spade(Nj)=1
No. of total cards(S)=52
Probability= Nj/S=1/52
B)
=>Solution:
No. of ace of red colour(Na)=2
No. of total cards(S)=52
Probability= Na/S=2/52=1/26
C)
=>Solution:
No. of card numbered 5(N5)=4
No. of total cards(S)=52
Probability=N5/S=4/52=1/13
I hope this is correct answer.
=>Solution:
No. of jack of spade(Nj)=1
No. of total cards(S)=52
Probability= Nj/S=1/52
B)
=>Solution:
No. of ace of red colour(Na)=2
No. of total cards(S)=52
Probability= Na/S=2/52=1/26
C)
=>Solution:
No. of card numbered 5(N5)=4
No. of total cards(S)=52
Probability=N5/S=4/52=1/13
I hope this is correct answer.
Answered by
0
A.
no. of jack of spade in 52 cards is 1
p(jack of spade ) = No.of jack of spade
total no. of cards
p(jack of spade)= 1
52 Ans.
B.
no. of red color ace in a deck= 2
P(ace of red color)= No.of red color ace
Total no. of cards
p(ace of red color)= 2
50
p(ace of red color) = 1
25 Ans.
C.
No. of 5 no. card in a deck =4
P ( 5 no. card ) = No.of 5no. card
Total no. of card
P(5 no. card) = 4
50
p(5 no. card)= 2
25 ANS.
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