Math, asked by rsareen543, 6 hours ago

Find the probability of 53 Sundays in a non leap year.​

Answers

Answered by FFLOVERADITYA
1

ANSWER-

1 remaining day can be Sunday, Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday. Total of 7 outcomes, the favourable outcome is 1. ∴ probability of getting 53 Sundays = 1 / 7...

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Answered by anshikaixd
0

Answer:

2

Step-by-step explanation:

1 remaining day can be Sunday, Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday. Total of 7 outcomes, the favourable outcome is 1. ∴ probability of getting 53 Sundays = 1 / 7

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