Find the probability of a non-leap year selected at random will contain 53 Sundays
Answers
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Answer:
The probability of an event is the ratio of a number of favorable outcomes to the total number of favorable outcomes of the event and lies between 0 and 1.
Answer: The probability of getting 53 Sundays in a non-leap year is 1/7
Let's find the probability of getting 53 Sundays in a non-leap year.
Explanation:
A non-leap year has 365 days.
In 365 days, there are 52 weeks and 1 day
In 52 weeks, the number of Sundays will be 52.
1 remaining day can be Sunday, Monday, Tuesday, Wednesday, Thursday, Friday, Saturday
We can have any one of these days out of 7 days
Hence, out of these 7 outcomes, the favorable outcome is 1
Therefore, Probability of getting 53 Sundays in a non-leap year = 1 / 7
Answer:
The probability of a non-leap year selected at random will contain 53 Sundays is 1/7.
Step-by-step explanation:
There are 365 days in a non-leap year.
There are 52 weeks and 1 day in a 365-day year.
The number of Sundays in 52 weeks will be 52.
Sunday, Monday, Tuesday, Wednesday, Thursday, Friday, and Saturday are all possibilities for the remaining day.
We can have any of these days out of a total of seven.
As a result, the most favourable outcome is 1 out of 7 possible outcomes.
As a result, the chance of having 53 Sundays in a non-leap year is 1 in 7.